Ncert Exercises & Solutions

One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the center) is:
1. $T$
2. $T-\frac{mv^2}{l}$
3. $T+\frac{mv^2}{l}$
4. zero

T = tension on the string.

(i) T

The net force T on the particle is directed towards the centre. It provides the centripetal force required by the particle to move along a circle.

$F = T = \frac{{mv}^{2}}{l}$ $F = T = \frac{{mv}^{2}}{l}$

Where F is the net force acting on the particle.

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