Ncert Exercises & Solutions

A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m/s to 3.5 m/s in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

$G i v e n,$

$m = 3 k g$

$u = 2 m / s$

$v = 3.5 m / s$

$t = 25 s$

$A s v = u + a t$

$\Rightarrow a = \frac{v - u}{t}$

$N o w, F = m a = m (\frac{v - u}{t})$

$\Rightarrow F = \frac{3.0 (3.5 - 2.0)}{25}$

$= 0.18 N (A l o n g t h e d i r e c t i o n o f m o t i o n)$

Question 5.7:

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