Ncert Exercises & Solutions

A proton is kept at rest. A positively charged particle is released from rest at a distance \(d\) in its field. Consider two experiments; one in which the charged particle is also a proton and in another, a positron. At the same time \(t\), the work done on the two moving charged particles is:

1.	same as the same force law is involved in the two experiments.
2.	less for the case of a position, as the position moves away more rapidly and the force on it weakens.
3.	more for the case of a position, as the position moves away from a larger distance.
4.	same as the work done by charged particle on the stationary proton.

Step 1: Find the force in two cases.

Force between two protons is the same as that of between proton and a positron.

Step 2: Find the work done in each case.

As positron is much lighter than a proton. it moves away through a much larger distance compared to proton.

We know that work is done = force x distance. As forces are the same in the case of proton and Position but distance moved by position is larger, hence, work done will be more.

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