Ncert Exercises & Solutions

Two identical current-carrying coaxial loops, carry current \(I\) in an opposite sense. A simple amperian loop passes through both of them once. Calling the loop as \(C\),

(a)	\(\oint B\cdot dl= \mp 2\mu_0 I\)
(b)	the value of \(\oint B\cdot dl\) is independent of the sense of \(C\).
(c)	there may be a point on \(C\) where \(B\) and \(dl\) are perpendicular.
(d)	\(B\) vanishes everywhere on \(C\).

Which of the above statements are correct?
1. (a) and (b)
2. (a) and (c)
3. (b) and (c)
4. (c) and (d)

(3) Hint: The magnetic field depends on the current.

Step 1: Applying the Ampere's circuital law, we have,

\oint_{c} B . d l = μ_{0} (I - I) = 0

(because the current is in the opposite sense.)

Step 2: Also, there may be a point on C where B and dl are perpendicular and hence;

\oint_{c} B . d l = 0

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions