If the RMS current in a 50 Hz50 Hz AC circuit is 5 A5 A, the value of the current 1300 s1300 s after its value becomes zero is:

1. 52 A52 A 2. 532 A532 A
3. 56 A56 A 4. 52 A52 A
(b) Hint: The current varies periodically in the circuit.(b) Hint: The current varies periodically in the circuit.
Step 1: Given, ν=50 Hz, Irms=5A
                 t=1300s
We have to find I(t).
Step 2: I0=Peak value=2Irms =2×5
    =52A
Step 3: I=I0sinωt =52sin2πνt=52 sin2×50×1300
  =52sinπ3=52×32=53/2 A