Ncert Exercises & Solutions

The electric field intensity produced by the radiations coming from \(100~\text{W}\) bulb at a \(3~\text{m}\) distance is \(E\). The electric field intensity produced by the radiations coming from \(50~\text{W}\) bulb at the same distance is:
1. \(\dfrac{E}{2}\)
2. \(2E\)
3. \(\dfrac{E}{\sqrt2}\)
4. \(\sqrt2E\)

Hint: The intensity of the radiation depends on the power of the bulb.

Step 1: We know that,

E_{0} \propto P_{av}

∴ \frac{E'}{E} = \frac{P_{av}'}{P_{av}}

E' = \frac{50}{100} E = \frac{E}{2}

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