Consider the diffraction pattern for a small pinhole. As the size of the hole is increased:
| (a) | the size decreases | (b) | the intensity increases |
| (c) | the size increases | (d) | the intensity decreases |
| 1. | (a), (b) | 2. | (a), (c) |
| 3. | (b), (d) | 4. | (c), (d) |
(a, b) Hint: The size and intensity of the image depend on the size of the hole.
Step 1: Find the change in size.
(1) When 'a' decreases, 'w' increases.
So, size decreases.
Step 2: Find the change in intensity.
(2) Now, light energy is distributed over a small area and intensity. As the area is area decreasing, so intensity increases.
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