Ncert Exercises & Solutions

Let \(E_{n} = \dfrac{- 1}{8 \varepsilon_{0}^{2}} \dfrac{m e^{4}}{n^{2} h^{2}}\) be the energy of the \(n^\text{th}\) level of H-atom. If all the H-atoms are in the ground state and radiation of frequency \(\dfrac{\left(\right. E_{2} - E_{1} \left.\right)}{h}\) falls on it, then:

(a)	it will not be absorbed at all.
(b)	some of the atoms will move to the first excited state.
(c)	all atoms will be excited to the \(n = 2\) state.
(d)	no atoms will make a transition to the \(n = 3\) state.

Choose the correct option:
1. (b, d)
2. (a, d)
3. (b, c, d)
4. (c, d)

(1) Hint: The excitation of the atoms depends on the energy given to them.

When all the H-atoms are in the ground state and radiation of frequency

\frac{(E_{2} - E_{1})}{h}

falls on it, some of atoms will move to the first excited state and no atoms will make a transition to the n = 3 state.

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