If there were only one type of charge in the universe, then:
(a) \(\oint_s {E} . {dS} \neq 0\) on any surface 
(b) \(\oint_s {E} . {dS} = 0\) if the charge is outside the surface. 
(c) \(\oint_s {E} . {dS}\) could not be defined.
(d) \(\oint_s {E} . {dS}=\frac{q}{\epsilon_0}\) if charges of magnitude \(q\) were inside the surface.
Choose the correct statement(s):
 
1. (a) and (d) 2. (a) and (c)
3. (b) and (d) 4. (c) and (d)
Hint: Use Gauss' law.
 
Explanation: The Gauss' law states that \(\oint_s {E} . {dS}=\frac{q}{\epsilon_0}\) where \(q\) is the charge enclosed by the surface. If the charge is outside the surface, then the charge enclosed by the surface is equal to \(0\) and thus, \(\oint_s {E} . {dS} = 0.\) Here, the electric flux doesn't depend on the type or nature of the charge.
Hence, option (3) is the correct answer.