Hint: Use Q=ne.
Step 1: Find the no. of Al-atoms present in one paisa coin.
Given,
Mass of a paisa coin = 0.75 g
The atomic mass of aluminium =26.9815 g
Avogadro's number = 6.023 x 1023
Number of aluminium atoms in one paisa coin,
Step 2: Find the amount of positive or negative charge on one paisa coin.
As the atomic number of Al is 13, each atom of Al contains 13 protons and 13 electrons.
The magnitude of positive and negative charges in one paisa coin = Nxzxe
This is a very large amount of charge. Thus, we can conclude that ordinary neutral matter contains an enormous amount of charges