Q 1.15)
Consider a uniform electric field E = 3 × 103 î N/C.
(a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the y z – plane?
(b) What is the flux through the same square if the normal to its plane makes a 60 ° angle with the x-axis?
(a)
Magnitude of electric field intensity, E = 3 × 103 N / C
Side of the square, s = 10 cm = 0.1 m
Area of the square, A = s2 = 0.01 m2
The plane of the square is parallel to the y – z plane. Hence, the angle between the area vector and the electric field, θ = 0°.
Flux ( φ ) through the plane,
φ = EA cos θ
φ = 3 × 103 × 0.01 × cos0°
φ = 30 N m 2 /C
(b) Plane makes an angle of 60 ° with the x-axis.
Hence, θ = 60°
Flux, φ = EAcosθ
Flux, φ = 3 × 10 3 × 0.01 × cos60°
Flux, φ = 30 x 0.5
Flux, φ = 15 N m 2 /C
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