An inflated rubber balloon contains one mole of an ideal gas, has a pressure \(P,\) volume \(V\) and temperature \(T.\) If the temperature rises to \(1.1T,\) and the volume is increased to \(1.05V,\) the final pressure will be:

1. \(1.1P\)
2. \(P\)
3. less than \(P\)
4. between \(P\) and \(1.1P\)

(d) Hint: Use the ideal gas equation.
We know for an ideal gas, pV =nRT                                (Ideal gas equation)
n= Number of moles, p = Pressure, V = Volume, R =Gasconstant, T =Temperature
                              n=pVRT
Step 1: Find the final pressure in the balloon.
As the number of moles of the gas remains fixed, hence, we can write:
 P1V1RT1=P2V2RT2
P2=(P1V1)T2V2T1
=(P)(V)(1.1T)(1.05)V(T)       [P1=P]
=P×1.11.05
=P(1.0476)1.05 P
Hence, the final pressure P2 lies between p and 1.1p.