Ncert Exercises & Solutions

A system goes from P to Q by two different paths in the P-V diagram as shown in the figure. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?

Hint: Use the first law of thermodynamics.

Step 1: Write down the given data.

For path 1, Heat given,

Q_{1}

= + 1000J

Work done, =

W_{1} (l e t)

For path 2,

Work done

(W_{2}) = (W_{1} - 100) J

Heat given,

Q_{2} = ?

Step 2: Use the first law of thermodynamics.

As the change in internal energy between two states for different path is the same,

∴ ∆ U = Q_{1} - W_{1} = Q_{2} - W_{2}

100 - W_{1} = Q_{2} - (W_{1} - 100)

\Rightarrow Q_{2} = 1000 - 100 = 900 J

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