Ncert Exercises & Solutions

11.13 A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500°C and then placed on a large ice block. What is the maximum amount of ice that can melt?

(Specific heat of copper = $0.39 J g^{- 1} K^{- 1}$ ; the heat of fusion of water = 335 J/gm).

Mass of the copper block, m = 2.5 kg = 2500 g

The maximum heat the copper block can lose, Q = mcΔθ = 2500 × 0.39 × 500 = 487500 J

Let m $_{1}$ gm be the amount of ice that melts when the copper block is placed on the ice block.

The heat gained by the melted ice, Q = m $_{1}$ L = the heat lost by the copper block

$∴ m_{1} = \frac{Q}{L} = \frac{487500}{335} = 1455.22 g$

Hence, the maximum amount of ice that can melt is 1.45 kg.

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