Ncert Exercises & Solutions

Question 9.15:
Determine the volume contraction of a solid copper cube, 10 cm on an edge, when
subjected to a hydraulic pressure of 7.0 ×10 $^{6}$ Pa.

The bulk modulus is given by, B= $\frac{P}{\frac{∆ V}{V}}$

$∴ ∆ V = \frac{{Pl}^{3}}{B} = \frac{7 \times 10^{6} \times {(0.1)}^{3}}{140 \times 10^{9}} = 5 \times 10^{- 8} m^{3} = 5 \times 10^{- 2} {cm}^{- 3}$

Therefore, the volume contraction of the solid copper cube is $5 \times 10^{- 2} {cm}^{- 3} .$

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