The variation of quantity \(A\) with quantity \(B\) is plotted in the given figure which describes the motion of a particle in a straight line.
           
Consider the following statements:

(a) Quantity \(B\) may represent time.
(b) Quantity \(A\) is velocity if motion is uniform.
(c) Quantity \(A\) is displacement if motion is uniform.
(d) Quantity \(A\) is velocity if motion is uniformly accelerated.


Select the correct option:
1. (a), (b), (c)
2. (b), (c), (d)
3. (a), (c), (d)
4. (a), (c)

Hint: Recall the concept of uniform motion and uniformly accelerated motion.

Step 1: Find the nature of the displacement-time graph in uniform motion.
When we are calculating the velocity of a displacement-time graph we have to take the slope. Similarly, we have to take the slope of the velocity-time graph to calculate acceleration.

Step 2: Find the nature of the velocity-time graph for uniformly accelerated motion.
When the slope is constant motion will be uniform. When we are representing motion by a graph it may be displacement-time, velocity-time or acceleration-time hence, B may represent time. For uniform motion, the velocity-time graph should be a straight line parallel to the time axis. For uniform motion velocity is constant hence slope will be positive. Hence quantity A is displacement.
Therefore, for uniformly accelerated motion slope will be positive and A will represent velocity.

Hence, option (3) is the correct answer.