Ncert Exercises & Solutions

Among the following, the correct order of energies of molecular orbitals of N₂ is:

1. $(π 2 p_{y}) < (σ 2 p_{z}) < (π * 2 p_{x}) \approx (π * 2 p_{y})$

2. $(π 2 p_{y}) > (σ 2 p_{z}) > (π * 2 p_{x}) \approx (π * 2 p_{y})$

3. $(π 2 p_{y}) < (σ 2 p_{z}) \approx (π * 2 p_{x}) \approx (π * 2 p_{y})$

4. $(π 2 p_{y}) > (σ 2 p_{z}) < (π * 2 p_{x}) \approx (π * 2 p_{y})$

Hint: Energy of σ 2 p z molecular orbital is more than π * 2 p x ≈ π * 2 p y molecular orbital .

Explanation:

Step 1: The MOT diagram for $N_{2}$ is as follows:

draw the molecular orbital diagram of n2 also find its bond order and magnetic character - Chemistry - TopperLearning.com | 4s4p942zz

Step 2:

So According to the above molecular orbital diagram

The order of energies of molecular orbitals of N₂ is as follows:

$(π 2 p_{y}) < (σ 2 p_{z}) < (π * 2 p_{x}) \approx (π * 2 p_{y})$