Ncert Exercises & Solutions

38. Write Lewis structure of ${O_{2}}^{-}$ ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?

The Lewis structure of

{O_{2}}^{-}

Oxygen atom carrying no charge has six electrons, so its oxidation number is zero. But oxygen atom carrying - 1 charge has 7 electrons, so its oxidation number is -1.

Average oxidation number of each oxygen atom

= \frac{1}{2}

{O_{2}}^{-} = 2 x = - 1

x = - \frac{1}{2}

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