Ncert Exercises & Solutions

Match the species given in Column I with the properties mentioned in Column II.

Column I	Column II
A. \(\text{BF}^-_4\)	1. Oxidation state of the central atom is +4
B. AlCl₃	2. Tetrahedral shape
C. SnO	3. Lewis acid
D. PbO₂	4. Can be further oxidized

Codes:

Hint: The hybridization of B in

{BF}_{4}^{-}

A. In

{BF}_{4}^{-}

, boron hybridization is sp³ hybridisation. The shape is tetrahedral.

B. In

{AlCl}_{3}

, Al octet is not completed. Hence, AlCl₃ acts as Lewis acid.

C. In

SnO

, Sn²⁺ can show a +4 oxidation state. Hence, it can be further oxidised.

D. Oxidation state of Pb in PbO₂ is +4. Due to the inert pair effect, Pb⁴⁺ is less stable than Pb²⁺, acts as a strong oxidising agent.