Ncert Exercises & Solutions

Electrophilic addition reactions proceed in two steps. The first step involves the addition of an electrophile. The major intermediate formed in the first step is:

$\mathrm{H}_3 \mathrm{C}-\mathrm{HC}=\mathrm{CH}_2+\mathrm{H}^{+} \rightarrow \text { ? }$

1. $2 °$ carbanion

2. $1 °$ carbocation

3. $2 °$ carbocation

4. $1 °$ carbanion

Hint: Stability of carbocation

When electrophile attacks

{CH}_{3} - CH = {CH}_{2}

delocalisation of electrons can take place, in two possible ways

Carbocation X is

2^{o}

and carbocation Y is

1^{o}

. As

2 °

carbocation is more stable than

1 °

carbocation. Thus, option third correct.

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions