Ncert Exercises & Solutions

The relative reactivity of $1 °, 2 °$ and $3 °$ hydrogen's towards chlorination is 1 : 3.8 : 5. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.

The given organic compound is

This compound has 9 primary hydrogen, 2 secondary and one tertiary hydrogen atoms. The relative

1 °, 2 °

and

3 °

hydrogen atoms chlorination is 1:3.8:5. Relative amount of product after chlorination=Number of hydrogen

\times

relative reactivity

Relative 1 ° halide 2 ° halide 3 ° halide

Amount 9 \times 1 = 9 2 \times 3.8 = 7.6 1 \times 5 = 5

Total amount of mono chloro product

= 9 + 7.6 + 5 = 21.6

Percentage of

1 °

mono chloro product

= \frac{9}{21.6} \times 100 = 41.7 %

Percentage of

2 °

mono chloro product

= \frac{7.6}{21.6} \times 100 = 35.2 %

Percentage of

3 °

mono chloro product

= \frac{5}{21.6} \times 100 = 23.1 %

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions