Ncert Exercises & Solutions

4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molarity of the resultant solution is:

1.	0.004 M	2.	0.008 M
3.	0.012 M	4.	0.016 M

Hint: $M_{1} V_{1} = M_{2} V_{2}$

Step 1:

Given, M₁ = 0.02M, V₁ =4L, M₂ =?, V₂ = 4L + 1L = 5L

Step 2:

As we Know, M₁V₁ = M₂V₂

0.02 x 4L = M₂ x 5L

M₂ =

\frac{0.08}{5}

= 0.016 M