NEETprep Answer: (b,c)
(a) Cerium (Z = 57) = Electronic configuration =
Oxidation state of Ce = +3, +4
(b) Europium (Z= 63) = Electronic configuration =
Eu = +2 , +3
(c) Ytterbium (Z = 70) = Electronic configuration =
Oxidation state of Yb = +2 , +3
(d) Holmium (Z = 67) = Electronic configuration =
Oxidation state of Ho = +3
(a) Cerium (Z = 57) = Electronic configuration =
Oxidation state of Ce = +3, +4
(b) Europium (Z= 63) = Electronic configuration =
Eu = +2 , +3
(c) Ytterbium (Z = 70) = Electronic configuration =
Oxidation state of Yb = +2 , +3
(d) Holmium (Z = 67) = Electronic configuration =
Oxidation state of Ho = +3
NCERT REFRENCE: PAGE NO. 236, TABLE NO. 8.9