Ncert Exercises & Solutions

Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type $Pd {(C_{6} H_{5})}_{2} (NCS)_{2}$ $Pd {(C_{6} H_{5})}_{2} (NCS)_{2}$ and $[P d {(C_{6} H_{5})}_{2} {(S C N)}_{2}]$ $[P d {(C_{6} H_{5})}_{2} {(S C N)}_{2}]$ are:

1. Linkage isomers
2. Coordination isomers
3. Ionization isomers
4. Geometrical isomers

The ligand(s) which has two different bonding sites are known as ambident ligands

e.g., NCS, NO $_{2}$ $_{2}$ etc.

Here, NCS has two binding sites at N and S,

Hence, NCS (thiocyanate) can bind to the metal ion in two ways

$M \leftarrow N C S o r M \to S N C$ $M \leftarrow N C S o r M \to S N C$

Thus, coordination compounds containing NCS as a ligand can show linkage

isomerism i.e. $[P d {(C_{6} H_{5})}_{2} {(S C N)}_{2}]$ $[P d {(C_{6} H_{5})}_{2} {(S C N)}_{2}]$ and $[P d {(C_{6} H_{5})}_{2} {(N C S)}_{2}]$ $[P d {(C_{6} H_{5})}_{2} {(N C S)}_{2}]$ ]are linkage isomers,

Hence, correct choice is (a).

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