Explain why [Fe(H]
[Fe(CN)6]3- has a value of only 1.74 BM?
Ans/. As we know μm=√n(n+2BM
Where, μ=magnetic moment
it μ=number of unpaired electrons
and μ=1.74 i.e., n=1
μ=5.92 i.e., n=5
[Fe(CN)6]3-involves d2sp3hybridisation with one unpaired electron (as shown by its
magnetic moment 1.74 BM) and [Fe(H20)6]3+involves sp3d2hybridisation with five
unpaired electrons (because magnetic moment equal to 6.92 BM)
CN- is stronger ligand than H2,O according to specttochemical series.∆0>P for CN-hence,
fourth electron will pair itself, Whereas for water pairing will not happen for [Fe(CN)6]3- the
electronic configuration of Fe3+ is
One unpaired electron
For [Fe(H]
Five unpaired electron
Hence, [Fe(CN)6]3- and [Fe(H2O)6]3+ are inner obital an douter orbital complex respectively
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