Ncert Exercises & Solutions

Match the complex species given in Column I with the possible isomerism given in Column II and assign the correct code.

Column I

(Complex species)

Column II

(Isomerism)

A. ${[Co {({NH}_{3})}_{4} {Cl}_{2}]}^{+}$

1. Optical isomerism

B. $cis - {[Co {(en)}_{2} {Cl}_{2}]}^{+}$

2. lonisation Isomerism

C. $[Co {({NH}_{3})}_{5} ({NO}_{2})] {Cl}_{2}$

3. Coordination Isomerism

D. $[Co {({NH}_{3})}_{6}] [Cr {(CN)}_{6}]$

4. Geometrical Isomerism

Codes:

A B C D

1. 2 3 4 1

2. 3 1 5 2

3. 5 4 3 2

4. 4 1 2 3

Isomerism in coordination compounds is decided by the type of ligands, geometry of

coordination compound and arrangement of ligands.

A. ${[Co {({NH}_{3})}_{4} {Cl}_{2}]}^{+}$ shows geometrical isomerism due to the presence of two types of ligand

whose ${[Co {({NH}_{3})}_{4} {Cl}_{2}]}^{+}$ arrangement around the central metal ion.

b. $cis - {[Co {(en)}_{2} {Cl}_{2}]}^{+}$ shows optical isomer due to its non-superimposable mirror image
relationship.

c. $[Co {({NH}_{3})}_{5} ({NO}_{2})] {Cl}_{2}$ shows ionization isomer due to its interchanging ligand from
outside the ionization sphere.

D. $[Co {({NH}_{3})}_{6}] [Cr {(CN)}_{6}]$ shows coordination isomer due to interchanging of ligand in
between two metal ions from one coordination sphere to another coordination sphere.

Hence, the correct choice is 4.

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