Ncert Exercises & Solutions

9.21 [Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colours in dilute solutions. Why?

The colour of a particular coordination compound depends on the magnitude of the crystalfield splitting energy, ∆. This CFSE in turn depends on the nature of the ligand. In case of $[F e {(C N)}_{6}]^{4 -} a n d [F e (H$ ₂O)6]2+, the colour differs because there is a difference in the CFSE. Now, $C N^{-}$ is a strong field ligand having a higher CFSE value as compared to the CFSE value of water. This means that the absorption of energy for the intra d-d transition also differs. Hence, the transmitted colour also differs.

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