1. Identify the longest carbon chain: The compound has a chain of four carbon atoms. Therefore, the parent chain is butane.

2. Identify and number the substituents:

   • Bromine is attached to the first carbon atom. (Number the carbon chain from the end that gives the bromine the lowest possible number.)
   • The methyl group is attached to the second carbon atom.

3. Assign prefixes and position numbers:

   • The bromine atom attached to the first carbon is indicated by the prefix "1-bromo".
   • The ethyl group attached to the third carbon is indicated by the prefix "2- methyl".

4. Combine the parts to form the IUPAC name: Combine the prefixes alphabetically, followed by the word root for the longest carbon chain and the suffix for the alkane.

The correct IUPAC name for the given compound is 1-bromo-2-methyl butane.