What is the correct order of reactivity of alcohols in the following reaction?
                R-OH+HCl  ZnCl2R-Cl +H2O

1. 1° > 2°> 3° 2. 1° < 2°> 3°
3. 3°> 2°> 1°  4. 3°> 1°> 2°

Hint: Lucas Reagent

The given reaction is nucleophilic substitution reaction in which -OH group is replaced by -Cl. Tertiary alcohols, when react with HCI in presence of ZnCl2 form tertiary carbocation.

This intermediate 3° carbocation is more stable than 2° carbocation as well as 1° carbocation. Higher the stability of intermediate, higher will be the reactivity of reactant molecule

So, the order of reactivity of alcohols in the given reaction is 3° > 2°> 1° and correct