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$\left(\mathrm{Yellow} \mathrm{ppt}\right)\stackrel{{\mathrm{K}}_2{\mathrm{CrO}}_4}{\leftarrow }\mathrm{X}\stackrel{\mathrm{dil}. \mathrm{HCl}}{\to }$
$\left(\mathrm{Yellow} \mathrm{ppt}\right) +\mathrm{Z}\uparrow (\mathrm{pungent} \mathrm{smelling} \mathrm{gas})$
If X gives a green flame test, then X is:
1. ${\mathrm{MgSO}}_4$
2. ${\mathrm{BaS}}_2{\mathrm{O}}_3$
3. ${\mathrm{CuSO}}_4$
4. ${\mathrm{PbS}}_2{\mathrm{O}}_3$

The pair of compounds, that cannot exist together in a solution is -
1. ${\mathrm{NaHCO}}_3 \mathrm{and} \mathrm{NaOH}$
2. ${\mathrm{Na}}_2{\mathrm{CO}}_3 \mathrm{and} \mathrm{NaOH}$
3. ${\mathrm{NaHCO}}_3 \mathrm{and} {\mathrm{Na}}_2{\mathrm{CO}}_3$
4. ${\mathrm{NaHCO}}_3 \mathrm{and} {\mathrm{H}}_2\mathrm{O}$

${\mathrm{Mg}}_2{\mathrm{C}}_3+{\mathrm{H}}_2\mathrm{O}\to \mathrm{X} \left(\mathrm{organic} \mathrm{compound}\right)$ compound X is 
1. ${\mathrm{C}}_2{\mathrm{H}}_2$
2. ${\mathrm{CH}}_4$
3. Propyne
4. Ethene

Solution of sodium metal in liquid ammonia 
is a strong reducing agent due to presence of
1. solvated sodium ions
2. solvated hydrogen ions
3. sodium atoms or sodium hydroxide
4. solvated electrons

The order of solubility of lithium halides in non-polar solvents follows the order
1. LiI > LiBr > LiCl > LiF
2. LiF > LiI > LiBr > LiCl
3. LiCl > LiF > LiI > LiBr
4. LiBr > LiCI > LiF > LiI

The compound which has no -O-O- bond is
1. ${\mathrm{BaO}}_2$
2. ${\mathrm{Na}}_2{\mathrm{O}}_2$
3. ${\mathrm{CrO}}_5$
4. ${\mathrm{Fe}}_2{\mathrm{O}}_3$

Highly pure dilute solution of sodium in ammonia
1. shows blue colouration due to solvated electrons
2. shows electrical conductivity due to solvated sodium ions only
3. shows red colouration due to solvated electrons but a bad 
    conductor of electricity
4. produces hydrogen gas or carbonate

$\mathrm{Y}\stackrel{∆,205°\mathrm{C}}{\leftarrow }{\mathrm{CaSO}}_4.2{\mathrm{H}}_2\mathrm{O}\stackrel{∆,120°\mathrm{C}}{\to }\mathrm{X}$, X and Y
are respectively
1. Plaster of paris, dead burnt plaster
2. dead burnt plaster, plaster of paris
3. CaO and plaster of paris
4. plaster of paris, mixture of gases

A paramagnetic compound among the following is -
1. ${\mathrm{K}}_2\mathrm{O}$
2. ${\mathrm{K}}_2{\mathrm{O}}_2$
3. ${\mathrm{Na}}_2{\mathrm{O}}_2$
4. ${\mathrm{RbO}}_2$

The order of melting point of chlorides of alkali metals is
1. LiCl > NaCl > KCl > CsCl
2. LiCl > NaCl < KCl > CsCl
3. NaCl > KCl > CsCl > LiCl
4. LiCl > NaCl > CsCl > KCl

The aqueous solutions of lithium salts
are poor conductor of electricity rather
than other alkali metals because of 
1. high ionisation energy
2. high electronegativity
3. lower ability of ${\mathrm{Li}}^{+}$ ions to 
    polarize water molecules
4. higher degree of hydration of 
    ${\mathrm{Li}}^{+}$ ions

The commercial method of preparation of potassium by reduction of molten KCl with metallic sodium at 850°C is based on the fact that -
1. Potassium is solid and sodium distils off at 850 °C.
2. Potassium is more volatile and distils off thus shifting the reaction forward.
3. Sodium is more reactive than potassium at 850 °C.
4. Sodium has less affinity to chloride ions in the presence of potassium ions.

${\mathrm{Be}}_2\mathrm{C}+{\mathrm{H}}_2\mathrm{O}\to \mathrm{BeO}+\mathrm{X}$
${\mathrm{CaC}}_2+{\mathrm{H}}_2\mathrm{O}\to \mathrm{Ca}{\left(\mathrm{OH}\right)}_2+\mathrm{Y}$
then X and Y respectively
1. ${\mathrm{CH}}_4, {\mathrm{CH}}_4$
2. ${\mathrm{CH}}_4, {\mathrm{C}}_2{\mathrm{H}}_6$
3. ${\mathrm{CH}}_4, {\mathrm{C}}_2{\mathrm{H}}_2$
4. ${\mathrm{C}}_2{\mathrm{H}}_2,{\mathrm{CH}}_4$

Which of the following statements are false ?
1. ${\mathrm{BeCl}}_2$ is a linear molecule in the vapour state
    but it is polymeric form in the solid state
2. Calcium hydride is called hydrolith
3. Carbides of both Be and Ca react with water
    to form acetylene
4. Oxides of both Be and Al are amphoteric 

The compound (s) formed upon combustion of sodium metal in excess air is (are)
1. ${\mathrm{Na}}_2{\mathrm{O}}_2$
2. ${\mathrm{Na}}_3\mathrm{N}$
3. ${\mathrm{NaO}}_2$
4. NaOH

Which of the following will not produce hydrogen gas
1. Reaction between Fe and dil. HCl
2. Reaction between Zn and conc. ${\mathrm{H}}_2{\mathrm{SO}}_4$
3. Reaction between Zn and NaOH
4. Electrolysis of NaCl in Nelson's cell

Both temporary and permanent hardness is removed on boiling water with
1. $\mathrm{Ca}{\left(\mathrm{OH}\right)}_2$
2. ${\mathrm{Na}}_2{\mathrm{CO}}_3$
3. ${\mathrm{CaCO}}_3$
4. CaO

Temporary hardness is caused due to presence of 
1. ${\mathrm{CaSO}}_4$
2. ${\mathrm{CaCl}}_2$
3. ${\mathrm{CaCO}}_3$
4. $\mathrm{Ca}{\left({\mathrm{HCO}}_3\right)}_2$

Calgon ( a water softener) is
1. ${\mathrm{Na}}_2\left[{\mathrm{Na}}_4{\left({\mathrm{PO}}_3\right)}_6\right]$
2. ${\mathrm{Na}}_4{\left[{\mathrm{Na}}_2\left({\mathrm{PO}}_3\right)\right]}_6$
3. ${\mathrm{Na}}_2{\left[{\mathrm{Na}}_4\left({\mathrm{PO}}_4\right)\right]}_6$
4. ${\mathrm{Na}}_4{\left[{\mathrm{Na}}_2\left({\mathrm{PO}}_4\right)\right]}_6$
 

The hair dyes available in the market generally contain two bottles, one containing the dye and the other hydrogen peroxide. Before applying the dye, the two solutions are mixed. The hydrogen peroxide
1. Is added to dilute the solution of the dye
2. Oxidised the dye to give the desired colour
3. Reduces the dye to give the desired colour
4. Acidifies the solution of the dye

When zeolite (hydrated sodium aluminium silicate) is treated with hard water, the sodium ions are exchanged with
1. ${\mathrm{H}}^{+}$ ions
2. ${\mathrm{Ca}}^{2+}$ions
3. ${\mathrm{SO}}_4^{2-}$ ions
4. ${\mathrm{OH}}^{-}$ ions 

Hydrogen peroxide is now generally prepared on an industrial scale by the
1. The action of ${\mathrm{H}}_2{\mathrm{SO}}_4$ on barium peroxide
2. The action of ${\mathrm{H}}_2{\mathrm{SO}}_4$ on sodium peroxide
3. Electrolysis of 50% ${\mathrm{H}}_2{\mathrm{SO}}_4$
4. Burning hydrogen in excess of oxygen

Which of the following statement is correct?

Polyphosphates are used as a water softening agent because they
1. Form soluble complexes with anionic species
2. Precipitate anionic species
3. Form soluble complexes with cationic species
4. Precipitate cationic species.

Which one of the following process will produce hard water
1. Saturation of water with ${\mathrm{CaSO}}_4$
2. Addition of ${\mathrm{Na}}_2{\mathrm{SO}}_4$ to water
3. Saturation of water with ${\mathrm{CaCO}}_3$
4. Saturation of water with ${\mathrm{MgCO}}_3$